# Chapter 5 - Section 5.1 - Fundamental Operations - Exercise - Page 214: 38

$369$

#### Work Step by Step

We are given: $x=-1$, $y=2$, $z=-3$ We take into account the order of operations: Parenthesis, Exponents, Multiplication/Division, Addition/Subtraction Thus, we have: $$3x^2(y-3z)^2-6x=3(-1)^2(2-3(-3))^2-6(-1)\\ =3(2+9)^2+6=3(11)^2+6 =369 .$$

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