Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Review - Page 157: 19

Answer

$$25 \times 10^{3} \ ns. $$

Work Step by Step

Since 1 $\mu s$= $10^{-6} \ s$ and $1~n s= 10^{-9} \ s$ W, we have $$25 \ \mu s= 25 \times 10^{-6} \ s= 25 \times 10^{-6} \times 10^{9} \ ns =25 \times 10^{3} \ ns. $$
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