Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Review - Page 157: 16


$$6100 \ g.$$

Work Step by Step

Since $1~kg =1000~g$, then we have $$6.1 \ kg=6.1\times 1000 \ g=6100 \ g.$$
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