Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.6 - Scientific Notation - Exercises - Page 127: 76


$$1.79\times 10^{-9}.$$

Work Step by Step

We divide the two numbers as follows: $$\frac{(0.0025)^2}{3500}=\frac{(2.5\times 10^{-3})^2}{3.5\times 10^3} \\ =\frac{6.25\times 10^{-6}}{3.5\times 10^3}=1.79\times 10^{-9}.$$
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