Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.6 - Scientific Notation - Exercises - Page 127: 77


$$1.17\times 10^{10}.$$

Work Step by Step

We have $$\left(\frac{48,000\times 0.0144 }{0.0064}\right)^2 =\left(\frac{(4.8\times10^4)(1.44\times10^{-2})}{6.4\times10^{-3}}\right)^2 \\=\left(\frac{6.912\times 10^2 }{6.4\times 10^{-3}}\right)^2\\ =(1.08\times 10^5)^2= 1.17\times 10^{10}.$$
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