Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Section 2.6 - Scientific Notation - Exercises - Page 127: 68


$$6.25 \times 10^{-18} .$$

Work Step by Step

We simplify by raising each factor to the exponent and then by division we have $$ \frac{(5 \times 10^{-6})^2}{4 \times 10^{6}}=\frac{25 \times 10^{-12}}{4 \times 10^{6}}=6.25 \times 10^{-18} .$$
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