Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 30

Answer

(a.) $34.9 \; cm$ (b.) $349 \; cm^2$ (c.) $152 \; cm^2$.

Work Step by Step

Given values are:- Radius $r=20.0\; cm$ Central angle $\theta = 100.0^{\circ}$ Length of the cord $c= 30.6 \; cm$. By using conversion factor $\frac{\pi \; rad}{180^{\circ}}$ central angle in radian measure is $\theta = 100.0^{\circ}\times \frac{\pi \; rad}{180^{\circ}}$ Simplify. $\theta = \frac{5\pi }{9}\; rad$ (a.) Formula for the length of the arc is $s=r\theta$. Substitute all values. $s=(20.0\;cm)(\frac{5\pi }{9})$ Simplify. $s=34.9\; cm$ (correct to one decimal place.) (b.) Formula for the area of the sector is $A=\frac{1}{2} r^2 \theta $ Substitute all values. $A=\frac{1}{2} (20.0 \; cm)^2 (\frac{5\pi }{9}) $ Simplify. $A=349 \;cm^2$ (Rounded value.) (c.) Formula for the area of the segment is $A=\frac{1}{2}r^2\theta-\frac{c\sqrt{4r^2-c^2}}{4}$ From the part (b.) $\frac{1}{2} r^2 \theta = 349.1\; cm^2 $ Substitute all values into the formula. $A=349.1\;cm^2-\frac{(30.6\; cm)\sqrt{4(20.0\;cm)^2-(30.6\; cm)^2}}{4}$ Simplify. $A=349.1\;cm^2-197.07$. $A=152 \;cm^2$ (Rounded value.)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.