Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 21

Answer

$98.5^o$

Work Step by Step

Using the relation $s=r\theta$, we have $\theta=\frac{s}{r}$; that is $$ \theta=\frac{s}{r}= \frac{0.860}{0.5}=1.72\ rad=1.72\times\frac{180}{\pi}=98.5^o .$$
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