Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.6 - Radian Measure - Exercise - Page 418: 18

Answer

$\frac{25\pi}{6}~m$

Work Step by Step

First, since $250^o= 250\times\frac{\pi}{180} \ rad=\frac{25\pi}{18} rad$, then using the relation $s=r\theta$, we have $$ s=r\theta=3\times \frac{25\pi}{18}=\frac{25\pi}{6}~m .$$
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