Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 398: 8


$17.3 \ m$

Work Step by Step

Since we have a right triangle with legs $a$, $b$ and a hypotenuse $c$, then by the Pythagorean theorem, we have $$c^2=a^2+b^2.$$ Since $c=25\ m $ and $a=18\ m$, then $b$ is given by $$ b=\sqrt{c^2-a^2}=\sqrt{25^2-18^2}=17.349 \ m\approx17.3 \ m .$$
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