Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 398: 12


$$19,600\ ft .$$

Work Step by Step

Since we have a right triangle with legs a, b and the hypotenuse c, then by the Pythagorean theorem, we have $$c^2=a^2+b^2.$$ Since $c=42,600 ft$ and $a=37,800 ft$, then $a$ is given by $$ b=\sqrt{c^2-a^2}=\sqrt{42,600^2-37,800^2}=19,600\ ft .$$
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