Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.3 - Triangles - Exercise - Page 398: 7


$$13.5 \ cm .$$

Work Step by Step

Since we have a right triangle with legs a, b and the hypotenuse c, then by the Pythagorean theorem, we have $$c^2=a^2+b^2.$$ Since $c=18.5 cm$ and $b= 12.6 cm$, then $a$ is given by $$ a=\sqrt{c^2-b^2}=\sqrt{18.5^2-12.6^2}=13.5 \ cm .$$
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