## Elementary Technical Mathematics

$2160\ in^3$
To find the area of the figure, find the area of the larger cube and subtract the area that has been cut away. $10\ in\times12\ in\times20\ in=2400\ in^3$ $3\ in\times4\ in\times20\ in=240\ in^3$ $2400\ in^3-240\ in^3=2160\ in^3$