## Elementary Technical Mathematics

Published by Brooks Cole

# Chapter 1 - Test - Page 103: 22

#### Answer

$6\dfrac{13}{16}$

#### Work Step by Step

Make the fractions similar using their LCD, which is $16$, to obtain: \begin{array}{cc} &&10\dfrac{2}{16} \\&- &\underline{3\dfrac{5}{16}} \end{array} Note that: $10\dfrac{2}{16} \\= (9+1)+\dfrac{2}{16} \\= 9+\dfrac{16}{16}+\dfrac{2}{16} \\=9+\dfrac{18}{16} \\=9\dfrac{18}{16}$ Thus, the given subtraction expression is equivalent to: \begin{array}{cc} &&9\dfrac{18}{16} \\&- &\underline{3\dfrac{5}{16}} \end{array} Subtract the whole numbers together and the fractions together to obtain: $=(9-3) + \left(\dfrac{18-5}{16}\right) \\=6+\dfrac{13}{16} \\=6\dfrac{13}{16}$

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