Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.14 - Rate, Base, and Part - Exercises: 43

Answer

Final sale price: First item = $\$45$ Second item = $\$51$

Work Step by Step

RECALL: $P=BR$ where $P$=part or amount (percentage), $B$=base, and $R$=rate The given problem involves: $B= \$100$ $R= 55\%$ (first item) $R_1=40\%$, $R_2 = 15\%$ (second item) Use the formula above to find the discounts ($P$). First Item: discount $=\$100 \times 55\% \\=\$100 \times 0.55 \\=\$55$ discounted price of first item = $\$100 - \$55 = \$45$ Second Item: First discount: $=\$100 \times 40\% \\=\$100 \times 0.40 \\=\$40$ Initial discounted price = $\$100-\$40 = \$60$ Second discount: $=\$60 \times 15\% \\=\$60 \times 0.15 \\=\$9$ final discounted price = $\$60-\$9 = \$51$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.