## Elementary Technical Mathematics

$25\%$
RECALL: $R=\dfrac{P}{B}$ where $B$=base, $P$=part, and $R$= rate or percent The given problem has: $B=0.600$ grain $P=0.150\%$ Solve for $R$ using the formula above to obtain: $R = \dfrac{P}{B} \\R = \dfrac{0.150}{0.600} \\P=0.25 \\P=0.25 \times 100\% \\P=25\$$Thus,$0.150$grain is$25\%$of$0.600\$ grain.