Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.14 - Rate, Base, and Part - Exercises - Page 84: 41


There was a $14.20\%$ decrease in Bill's hourly wage.

Work Step by Step

First, find the decrease in hourly wage: $=\$25.50-\$21.88 \\=\$3.62$ RECALL: $\text{percent decrease}=\dfrac{\text{decrease in value}}{\text{original value}}$ The given problem has: original value =$\$25.50$ decrease in value = $\$3.62$ Solve for the percent decrease using the formula above to obtain: percent decrease $= \dfrac{3.62}{25.50} \\=0.1419607843 \\=0.1419607843 \times 100\% \\=14.19607843\% \\\approx 14.20\%$ Thus, there was a $14.20\%$ decrease in Bill's hourly wages.
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