Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 0-32198-238-X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.7 Exercises: 32

Answer

$\vec{x}=\begin{bmatrix}1\\2\\-1\end{bmatrix}$

Work Step by Step

Since the third column of the matrix is the sum of the first column and two times the second column, we have the following: $ \begin{bmatrix}4&1&6\\-7&5&3\\9&-3&3\end{bmatrix}\begin{bmatrix}1\\2\\-1\end{bmatrix}=1\cdot\begin{bmatrix}4\\-7\\9\end{bmatrix}+2\cdot\begin{bmatrix}1\\5\\-3\end{bmatrix}+(-1)\cdot\begin{bmatrix}6\\3\\3\end{bmatrix}=\begin{bmatrix}0\\0\\0\end{bmatrix} $ Any nonzero constant multiple of this solution will also work as a nontrivial solution to the homogeneous equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.