#### Answer

$ \begin{bmatrix} \blacksquare&*&*\\ 0&\blacksquare&*\\ 0&0&\blacksquare \end{bmatrix} $

#### Work Step by Step

Recall that $\blacksquare$ represents a pivot and $*$ represents any numerical entry, including $0$. A matrix has linearly independent columns if and only if it contains a pivot in every column, leaving no free variables in the corresponding homogeneous matrix equation. By the rules defining an echelon matrix, the result must have the form above.