#### Answer

$ \begin{bmatrix} \blacksquare&*\\ 0&0 \end{bmatrix} $ $ \begin{bmatrix} 0&\blacksquare\\ 0&0 \end{bmatrix} $ $ \begin{bmatrix} 0&0\\ 0&0 \end{bmatrix} $

#### Work Step by Step

The columns of a matrix are linearly dependent if and only if at least one column of does not contain a pivot position. Hence, we can have a pivot position in the first column only, in the second column only, or in neither column.