Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Concept and Vocabulary Check - Page 516: 5

Answer

$-1$

Work Step by Step

When we multiply the numerator and denominator of a rational expression with a nonzero expression, we are multiplying the rational expression with 1. Multiplying with 1 does not change the value, so the resulting rational expression is equivalent to the initial one.. Here, we have: initial rational expression = $\displaystyle \frac{7}{(9-5x)}$. Multiply it with $1=\displaystyle \frac{A}{A}$, where A is some nonzero expression: $\displaystyle \frac{7}{(9-5x)}\cdot\frac{A}{A}=\frac{7\cdot A}{(9-5x)\cdot A}$ We want the resulting denominator to be $5x-9.$ $5x-9=-(9-5x)=(9-5x)(-1)$ so, we see that $A=-1.$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.