Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.4 - Adding and Subtracting Rational Expressions with Different Denominators - Concept and Vocabulary Check - Page 516: 3

Answer

$3$

Work Step by Step

When we multiply the numerator and denominator of a rational expression with a nonzero expression, we are multiplying the rational expression with 1. Multiplying with 1 does not change the value, so the resulting rational expression is equivalent to the initial one.. Here, we have: initial rational expression = $\displaystyle \frac{7}{8x}$. Multiply it with $1=\displaystyle \frac{A}{A}$, where A is some nonzero expression: $\displaystyle \frac{7}{8x}\cdot 1=\frac{7}{8x}\cdot\frac{A}{A}=\frac{7A}{8x\cdot A}$, We want the resulting denominator to be $24x$. So, A must equal $3$, in which case $\displaystyle \frac{7}{8x}=\frac{7}{8x}\cdot\frac{3}{3}=\frac{21}{24x}$
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