Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 7 - Section 7.2 - Multiplying and Dividing Rational Expressions - Exercise Set - Page 499: 24

Answer

$\displaystyle \frac{x+4}{x+2}$

Work Step by Step

Step by step multiplication of rational expressions: 1. Factor completely what you can 2. Reduce (divide) numerators and denominators by common factors. 3. Multiply the remaining factors in the numerators and multiply the remaining factors in the denominators. $(\displaystyle \frac{P}{Q}\cdot\frac{R}{S}=\frac{PR}{QS})$ --- Factor what we can: ... recognize a square of a sum: $a^{2}+2ab+b^{2}=(a+b)^{2}$ $x^{2}+4x+4=x^{2}+2(x)(2)+2^{2}=(x+2)^{2}$ $x^{2}+8x+16=x^{2}+2(x)(4)+4^{2}=(x+4)^{2}$ Also, use : $X^{3}=X\cdot X^{2}$ The problem becomes $...=\displaystyle \frac{(x+4)(x+4)^{2}\cdot(x+2)^{2}}{(x+2)(x+2)^{2}\cdot(x+4)^{2}}\qquad$ ... divide out the common factors $=\displaystyle \frac{(x+4)\fbox{$(x+4)^{2}$}\cdot\fbox{$(x+2)^{2}$}}{(x+2)\fbox{$(x+2)^{2}$}\cdot\fbox{$(x+4)^{2}$}}$ = $\displaystyle \frac{x+4}{x+2}$
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