Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 437: 88

Answer

The numbers $-27$ and $-19$ are negative, and they should be both positive, so the factorization is incorrect. (If both were positive, $+27$ and $+19$, then it would be correct)

Work Step by Step

If the trinomial $ax^{2}+bx+c$ can be factored, it will be in the form $(x+n)(x+m)$, where the product of integers n and m is $c$ their sum is $b.$ So if c is positive, both n and m have the same sign. If c is negative, n and m have different signs. Here, c is positive, so both n and m have the same sign. And, since b is positive, this sign must be "$+$" for both n and m. The numbers $-27$ and $-19$ are negative, and they should be both positive, so the factorization is incorrect. (If both were positive, $+27$ and $+19$, then it would be correct)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.