Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 437: 112

Answer

$(2x-5)(4x-1)$

Work Step by Step

Group in pairs... $...=[8x^{2}-2x]+[-20x+5]$ Apply the distributive property in each pair, taking gcf's to be 2x and -5 $= 2x(4x-1)+(-5)(4x-1)$ The gcf is $(4x-1)$... = $(2x-5)(4x-1)$
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