Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 437: 100



Work Step by Step

For the moment, substitute $x^{n}=y.$ The trinomial becomes $y^{2}+20y+99.$ We search for integer factors of 99 whose sum is 20... ... and we find 9 and 11, $=(y+9)(y+11)$ ... back-substitute $x^{n}=y$ = $(x^{n}+9)(x^{n}+11)$
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