Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set: 67



Work Step by Step

Factoring the negative $GCF= -16 ,$ the given expression, $ -16t^2+64t+80 ,$ is equivalent to \begin{array}{l}\require{cancel} -16(t^2-4t-5) .\end{array} The trinomial expression above has $c= -5 $ and $b= -4 .$ The possible factors of $c$ are $ \{ 1,-5 \} ,\{ -1,5 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ 1,-5 \}.$ Hence, the factored form of the given expression is \begin{array}{l}\require{cancel} -16(t+1)(t-5) .\end{array}
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