Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set: 15

Answer

$(x-3)(x+13)$

Work Step by Step

The given expression, $ y^2+10y-39 ,$ has $c= -39 $ and $b= 10 .$ The possible factors of $c$ are $ \{ 1,-39 \} ,\{ 3,-13 \} ,\{ -1,39 \} ,\{ -3,13 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ -3,13 \}.$ Hence, the factored form is \begin{array}{l}\require{cancel} (x-3)(x+13) .\end{array}
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