Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set: 65

Answer

$xy(x+y)(x-3y)$

Work Step by Step

Factoring the $GCF= xy ,$ the given expression, $ x^3y-2x^2y^2-3xy^3 ,$ is equivalent to \begin{array}{l}\require{cancel} xy(x^2-2xy-3y^2) .\end{array} The trinomial expression above has $c= -3 $ and $b= -2 .$ The possible factors of $c$ are $ \{ 1,-3 \} ,\{ -1,3 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ 1,-3 \}.$ Hence, the factored form of the given expression is \begin{array}{l}\require{cancel} xy(x+y)(x-3y) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.