Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.2 - Factoring Trinomials Whose Leading Coefficient is 1 - Exercise Set - Page 436: 65



Work Step by Step

Factoring the $GCF= xy ,$ the given expression, $ x^3y-2x^2y^2-3xy^3 ,$ is equivalent to \begin{array}{l}\require{cancel} xy(x^2-2xy-3y^2) .\end{array} The trinomial expression above has $c= -3 $ and $b= -2 .$ The possible factors of $c$ are $ \{ 1,-3 \} ,\{ -1,3 \} $. Among these factors, the pair whose sum is equal to $b$ is $\{ 1,-3 \}.$ Hence, the factored form of the given expression is \begin{array}{l}\require{cancel} xy(x+y)(x-3y) .\end{array}
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