Answer
$(4x+1)(16x^{2}-4x+1)$
Work Step by Step
$ 64x^{3}+1\qquad$...use the sum of two cubes:
$\mathrm{A}^{3}+\mathrm{B}^{3} = (\mathrm{A}+\mathrm{B})(\mathrm{A}^{2} - \mathrm{A}\mathrm{B} + B^{2})$
$=(4x)^{3}+1^{3}$
$=(4x+1)(16x^{2}-4x+1)$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 6 - Review Exercises - Page 479: 43
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