Answer
$-2(2x-1)(2x+3)$
Work Step by Step
$-8x^{2}-8x+6\qquad$...factor out the common term, $-2$.
$=-2(4x^{2}+4x-3)$
... Searching for two factors of $ac=-12$ whose sum is $b=4,$
we find$\qquad-2$ and $6.$
Rewrite the middle term and factor in pairs:
$=-2(4x^{2}-2x+6x-3)=$
$=-2[2x(2x-1)+3(2x-1)]$
=$-2(2x-1)(2x+3)$
