Answer
$(x-3)(x^{2}+3x+9)$
Work Step by Step
$ x^{3}-27\qquad$...use the difference of two cubes:
$\mathrm{A}^{3}-\mathrm{B}^{3} = (\mathrm{A}-\mathrm{B})(\mathrm{A}^{2} + \mathrm{A}\mathrm{B} + B^{2})$
$=(x)^{3}-3^{3}$
$=(x-3)(x^{2}+3x+9)$