Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Test - Page 416: 15


$$4x^2 + 12xy + 9y^2$$

Work Step by Step

We expand the expression to see the terms more clearly: $$(2x + 3y)(2x + 3y)$$ We use distributive property to multiply each term in the first binomial by each term in the second binomial: $$2x(2x) + 2x(3y) + 3y(2x) + 3y(3y)$$ Multiply to simplify: $$4x^2 + 6xy + 6xy + 9y^2$$ Group like terms: $$4x^2 + (6xy + 6xy) + 9y^2$$ Combine like terms: $$4x^2 + 12xy + 9y^2$$
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