Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Test - Page 416: 14


$$12a^2 - 13ab - 35b^2$$

Work Step by Step

We use distributive property to multiply each term in the first binomial by each term in the second binomial: $$3a(4a) - 7b(4a) + 5b(3a) - 7b(5b)$$ Multiply to simplify: $$12a^2 - 28ab + 15ab - 35b^2$$ Group like terms: $$12a^2 + (-28ab + 15ab) - 35b^2$$ Combine like terms: $$12a^2 - 13ab - 35b^2$$
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