Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Test - Page 416: 12

Answer

$$30$$

Work Step by Step

To evaluate this expression, we substitute $-2$ where we see $x$ and $3$ where we see $y$: $$4(-2)^2(3) + 5(-2)(3) - 6(-2)$$ Evaluate the exponent first: $$4(4)(3) + 5(-2)(3) - 6(-2)$$ Multiply to simplify: $$16(3) + 5(-6) + 12$$ $$48 - 30 + 12$$ Subtract first, according to order of operations: $$18 + 12$$ Add to evaluate the expression: $$30$$
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