## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set: 6

#### Answer

$-19$

#### Work Step by Step

Substituting $x=2$ and $y=-3$, the given expression, $3x^2y-4y+5 ,$ evaluates to \begin{array}{l}\require{cancel} 3(2)^2(-3)-4(-3)+5 \\\\= 3(4)(-3)-(-12)+5 \\\\= -36+12+5 \\\\= -24+5 \\\\= -19 .\end{array}

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