Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set: 35

Answer

$28a^{3}b^{5}+8a^{2}b^{3}$

Work Step by Step

Using the Distributive Property, the product of the given expression, $ 4ab^2(7a^2b^3+2ab) ,$ is \begin{array}{l}\require{cancel} 4ab^2(7a^2b^3)+4ab^2(2ab) \\\\= 28a^{1+2}b^{2+3}+8a^{1+1}b^{2+1} \\\\= 28a^{3}b^{5}+8a^{2}b^{3} .\end{array}
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