Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.4 - Polynomials in Several Variables - Exercise Set - Page 375: 2

Answer

$-5$

Work Step by Step

Substituting $x=2$ and $y=-3$, the given expression, $ x^2+3xy+y^2 ,$ evaluates to \begin{array}{l}\require{cancel} (2)^2+3(2)(-3)+(-3)^2 \\\\= 4-18+9 \\\\= -14+9 \\\\= -5 .\end{array}
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