Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.1 - Adding and Subtracting Polynomials - Exercise Set - Page 348: 36

Answer

$-\frac{2}{5}x^{4}$ + $x^{3}$ + $\frac{3}{8}x^{2}$

Work Step by Step

($\frac{2}{5}x^{4}$ + $\frac{2}{3}x^{3}$ + $\frac{5}{8}x^{2}$ + 7) + (-$\frac{4}{5}x^{4}$ + $\frac{1}{3}x^{3}$ - $\frac{1}{4}x^{2}$ - 7) The like terms are $\frac{2}{5}x^{4}$ and -$\frac{4}{5}x^{4}$ (both containing $x^{4}$) , $\frac{2}{3}x^{3}$ and $\frac{1}{3}x^{3}$ (both containing $x^{3}$) , $\frac{5}{8}x^{2}$ and - $\frac{1}{4}x^{2}$ (both containing $x^{2}$) , 7 and -7 both are constants We begin by grouping these pairs of like terms = ($\frac{2}{5}x^{4}$ -$\frac{4}{5}x^{4}$) + ($\frac{2}{3}x^{3}$ +$\frac{1}{3}x^{3}$) + ($\frac{5}{8}x^{2}$ - $\frac{1}{4}x^{2}$ )+ (7 - 7) =$-\frac{2}{5}x^{4}$ + $x^{3}$ + $\frac{3}{8}x^{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.