Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 5 - Section 5.1 - Adding and Subtracting Polynomials - Exercise Set: 33

Answer

$10x^{3}$ + 1

Work Step by Step

(9$x^{3} - x^{2}- x - \frac{1}{3}$) + ($x^{3} + x^{2} + x + \frac{4}{3}$) The like terms are 9$x^{3}$ and $x^{3} $(both containing $x^{3}$) , -$x^{2}$ and $x^{2}$ (both containing $x^{2}$) , -x and x (both containing r) , -$\frac{1}{3}$ and $\frac{4}{3}$ both are constants We begin by grouping these pairs of like terms = (9$x^{3}$ + $x^{3} $) + (-$x^{2}$ + $x^{2}$) + (-x + x)+ (-$\frac{1}{3}$ + $\frac{4}{3}$) =$10x^{3}$ + 1
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