Answer
$10x^{3}$ + 1
Work Step by Step
(9$x^{3} - x^{2}- x - \frac{1}{3}$) + ($x^{3} + x^{2} + x + \frac{4}{3}$)
The like terms are 9$x^{3}$ and $x^{3} $(both containing $x^{3}$) , -$x^{2}$ and $x^{2}$ (both containing $x^{2}$) , -x and x (both containing r) , -$\frac{1}{3}$ and $\frac{4}{3}$ both are constants
We begin by grouping these pairs of like terms
= (9$x^{3}$ + $x^{3} $) + (-$x^{2}$ + $x^{2}$) + (-x + x)+ (-$\frac{1}{3}$ + $\frac{4}{3}$)
=$10x^{3}$ + 1
