## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 5 - Section 5.1 - Adding and Subtracting Polynomials - Exercise Set - Page 348: 35

#### Answer

$-\frac{2}{5}x^{4}$ + $x^{3}$ - $\frac{1}{8}x^{2}$

#### Work Step by Step

($\frac{1}{5}x^{4}$ + $\frac{1}{3}x^{3}$ + $\frac{3}{8}x^{2}$ + 6) + (-$\frac{3}{5}x^{4}$ + $\frac{2}{3}x^{3}$ - $\frac{1}{2}x^{2}$ - 6) The like terms are $\frac{1}{5}x^{4}$ and -$\frac{3}{5}x^{4}$ (both containing $x^{4}$) , $\frac{1}{3}x^{3}$ and $\frac{2}{3}x^{3}$ (both containing $x^{3}$) , $\frac{3}{8}x^{2}$ and - $\frac{1}{2}x^{2}$ (both containing $x^{2}$) , 6 and -6 both are constants We begin by grouping these pairs of like terms = ($\frac{1}{5}x^{4}$ -$\frac{3}{5}x^{4}$) + ($\frac{1}{3}x^{3}$ +$\frac{2}{3}x^{3}$) + ($\frac{3}{8}x^{2}$ - $\frac{1}{2}x^{2}$ )+ (6 -6) =$-\frac{2}{5}x^{4}$ + $x^{3}$ - $\frac{1}{8}x^{2}$

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