Answer
$(\displaystyle \frac{7}{25},-\frac{1}{25})$ is a solution of the system.
Work Step by Step
An ordered pair is a solution to the system if it satisfies both equatons:
$ \begin{array}{lllll}
4(\frac{7}{25})+3(-\frac{1}{25}) & =1 & .... & 3(\frac{7}{25})-4(-\frac{1}{25}) & =1\\
\frac{28}{25}-\frac{3}{25} & =1 & & \frac{21}{25}+\frac{4}{25} & =1\\
\frac{25}{25} & =1 & & \frac{25}{25} & =1\\
TRUE & & & TRUE &
\end{array} $
$(\displaystyle \frac{7}{25},-\frac{1}{25})$ is a solution of the system.
