Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Test - Page 206: 6



Work Step by Step

$\frac{x}{10}$+$\frac{1}{3}$=$\frac{x}{5}$+$\frac{1}{2}$ 30($\frac{x}{10}$+$\frac{1}{3}$)=30($\frac{x}{5}$+$\frac{1}{2}$) $\frac{30x}{10}$+$\frac{30}{3}$=$\frac{30x}{5}$+$\frac{30}{2}$ 3x+10=6x+15 3x=6x+15-10 3x=6x+5 3x-6x=5 -3x=5 x=-$\frac{5}{3}$
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