Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Test: 10

Answer

w=$\frac{P-2l}{2}$

Work Step by Step

l=$\frac{P-2w}{2}$ 2l=$\frac{2(P-2w)}{2}$ 2l=P-2w 2l-P=-2w -1(2l-P)=-1(-2w) -2l+P=2w P-2l=2w $\frac{P-2l}{2}$=$\frac{2w}{2}$ $\frac{P-2l}{2}$=w w=$\frac{P-2l}{2}$
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