Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Test - Page 206: 17


l=150 yd w=75 yd

Work Step by Step

From the given description we know that l must equal 2w. Plug this value in for l in the perimeter equation and solve for w. P=2l+2w P=2(2w)+2w 450=2(2w)+2w 450=4w+2w 450=6w $\frac{250}{6}$=w 75=w w=75 yd l=2w l=2(75) l=150 yd
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