Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 142: 50



Work Step by Step

0.15y-0.1=2.5y-1.04 100(0.15y-0.1)=100(2.5y-1.04) 15y-10=250y-104 -10=250y-15y-104 -10=235y-104 -10+104=235y 94=235y $\frac{94}{235}$=y 0.4=y Check the answer. 1.15(0.4)-0.1=2.5(0.4)-1.04 0.06-0.1=1-1.04 -0.04=-0.04
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