Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set - Page 142: 53



Work Step by Step

0.4(2z+6)+0.1=0.5(2z-3) (10)(0.4)(2z+6)+(10)(0.1)=(10)(0.5)(2z-3) 4(2z+6)+1=5(2z-3) 8z+24+1=10z-15 8z+25=10z-15 25=10z-8z-15 25=2z-15 25+15=2z 40=2z 40$\div$2=z 20=z Check the answer. 0.4(2(20)+6)+0.1=0.5(2(20)-3) 0.4(40+6)+0.1=0.5(40-3) 0.4(46)+0.1=0.5(37) 18.4+0.1=18.5 18.5=18.5
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