Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 2 - Section 2.3 - Solving Linear Equations - Exercise Set: 63

Answer

x=$\frac{2}{3}$

Work Step by Step

7+2(3x-5)=8-3(2x+1) 7+6x-10=8-6x-3 (7-10)+6x=(8-3)-6x -3+6x=5-6x 6x=5+3-6x 6x=8-6x 6x+6x=8 12x=8 x=$\frac{8}{12}$ x=$\frac{2}{3}$
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