## Introductory Algebra for College Students (7th Edition)

Published by Pearson

# Chapter 1 - Section 1.8 - Exponents and Order of Operations - Exercise Set: 69

#### Answer

-$\frac{9}{40}$

#### Work Step by Step

-$\frac{9}{4}$($\frac{1}{2}$)+$\frac{3}{4}$$\div$$\frac{5}{6}$ First change the division to multiplication of the reciprocal -$\frac{9}{4}$($\frac{1}{2}$)+$\frac{3}{4}$$\times$$\frac{6}{5}$ Then multiply both sets of fractions -$\frac{9}{8}$+$\frac{18}{20}$ Then make both fractions have the least common denominator of 40 -$\frac{9(5)}{8(5)}$+$\frac{18(2)}{20(2)}$ -$\frac{45}{40}$+$\frac{36}{40}$ Then add -$\frac{9}{40}$

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