## Introductory Algebra for College Students (7th Edition)

$\frac{4}{3}$
[7+3(2$^3$-1)]$\div$21 First solve the exponent inside the parentheses [7+3(8-1)]$\div$21 Then subtract inside the parentheses [7+3(7)]$\div$21 Then multiply inside the brackets [7+21]$\div$21 Then add inside the brackets [28]$\div$21 Then divide $\frac{28}{21}$ Then reduce by 7 $\frac{4}{3}$